PLEASE ANSWER THIS! In the diagram, PQRS, JQK and LRK are straight lines
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J-
2yQ
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O
x
K
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M
33°
DO
R
L
2x/
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S
What is the size of the angle JKL?
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A Question 15
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37°
38°
36°
34°
35°

  38°

Step-by-step explanation:

The sum of angles that make a line is 180°; the sum of angles in a triangle is 180°. So, we have the following relations:

  2x +y +A = 180

  2y +x + B = 180

  A +B +33 = 180

Adding the first two equations and subtracting the third, we get ...

  (2x +y +A) +(2y +x +B) -(A +B +33) = 180 +180 -180

  3x +3y -33 = 180

  x + y - 11 = 60

  x + y = 71

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We know vertical angles are congruent, so in triangle QRK, we have ...

  2y +2x +∠K = 180

  ∠K = 180 -2x -2y = 180 -2(x +y) = 180 -2(71)

  ∠JKL = 38°

38 degrees

Step-by-step explanation:

answer: i realy don't get it that much can you me figer it out pleas you

step-by-step explanation:

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval