Asingle microvillus is a rod-like structure that is 1.0 μm in height. it has a hemispherical top approximately 0.1 μm in diameter. calculate the surface area of the cylinder that forms the "sides" of the microvillus rod. use 3.14 for π. enter your answer rounded to two decimal places. now calculate the surface area of the hemispherical top of the microvillus rod. use 3.14 for π.

We have that the surface of the cylinder is given by 2prh. The diameter is 0.1 μm, so the radius is 0.05 μm. Hence, substituting we get that the total surface area is 0.314 μm^2=2*0.05*1*3.14.

The surface of a hemisphere is half the surface of a sphere. The surface of a sphere is: 4pr^2. Hence, the hemisphere has an area of 2pr^2.  Substituting now again, we get:
μ.
This is the area of the top.

We can add these two areas to find the total area.