On earth, the solar constant is approximately I = 1367 W/m2 . This corresponds to the power per unit area that a detector at the edge of the earth atmosphere would sense if perpendicular to the solar rays. This value can be obtained from the sun/earth geometry and by considering the sun as a blackbody at Tsun = 6000 K emitting radiation according to EEbb = σσTT 4 where σσ = 5.67 × 10−8 W m−2K−4. Earth distance to sun = 150 000 000 km Mars to sun distance = 230 000 000 km With the information above, compute the solar constant in Mars. No need to do the actual calculation; instead, simply describe the step(s) you would take to solve the problem and list the relevant equation(s)

Explanation:

for earth -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₁²  x solar constant on earth , R₁ is distance between earth and sun.

for marsh -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₂²  x solar constant on Mars , R₂ is distance between earth and sun.

from two equation ,

4π R₂²  x solar constant on Mars = 4π R₁²  x solar constant on earth

solar constant on Mars = (R₁ / R₂ )² x solar constant on earth

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.

i think it's 35 meters