A625 kg elevator is pulled upward by a cable that exerts a 7250 n force. what is the acceleration of the elevator? (don't forget its weight)

The acceleration of the elevator is 1.8 m/s².

Explanation:

Given that,

Mass of elevator = 625 kg

Tension = 7250 N

We need to calculate the acceleration

Using equation of balance

Where, T = tension

m = mass

a = acceleration

Put the value into the formula

Hence, The acceleration of the elevator is 1.8 m/s².

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west