Mathematics, 27.08.2019 18:00 Yuii

Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. he handed out 2/3 of the chocolate bars and 3/5 of the toffee bars. how many packages of chocolates bar did rasheed buy?
(1) rasheed bought 1 fewer package of chocolate bars than toffee bars.
(2) rasheed handed out the same number of each kind of candy bar.

Answers: 2

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Answer from: LarryJoeseph

Rasheed bought 9 packages of chocolates bar.

Step-by-step explanation:

Let C be the number of packages of chocolate bars.

Let T be the number of packages of toffee bars.

Rasheed handed out 2/3 of 2C of the chocolate bars and 3/5 of 2T of the toffee bars.

(1) Rasheed bought 1 fewer package of chocolate bars than toffee bars.

Equation becomes:

C=T-1 .....(1)

(2) Rasheed handed out the same number of each kind of candy bar .

Equation becomes:

$\frac{2}{3}\times 2C =\frac{3}{5}\times 2T$

=> $\frac{4C}{3} =\frac{6T}{5}$

=> 20C=18T

=> 20C-18T=0

Taking out 2 common, we get

10C-9T=0 ......(2)

Substituting C=T-1 in (2)

10(T-1)-9T=0

=> 10T-10-9T=0

=> T-10=0

T = 10

As C=T-1

C=10-1

C = 9

Therefore, Rasheed bought 9 packages of chocolates bar.

Answer from: Quest

answer set (b) 0.5, 3/4 80% is in order from least to greatest.

step-by-step explanation:

in order to compare rational numbers to each other, it is much easier if they are in the same form. typically, the best form in which to evaluate rational numbers is in decimals. in order to convert a percent to a decimal, you would divide the given percentage by 100. you can also accomplish the conversion by moving the decimal point over two places to the left. for example, the decimal value of 80% is 80/100, or 0.8. in order to convert a fraction to a decimal, you need to divide the numerator by the denominator. for example, 3/4 is 0.75. so, for choice (b) 0.5 3/4 (0.75), 80% (0.8) is the only choice in which the numbers are in order from least to greatest.

Answer from: Quest

so the perpendicular line goes through the given pointyou would get a perpendicular line at some random location

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.

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Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each....

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