How to solve this equation 2(f+3)+4f=6+6f?

2f+6+4f=6+6f
6f+6-6=6-6+6f
6f=6f
This means f can equal any number which we call mathematically infinite solution or infinitely many solutions

Step 1: Simplify both sides of the equation.
2(f+3)+4f=6+6f
Simplify: (Show steps)
6f+6=6f+6
Step 2: Subtract 6f from both sides.
6f+6-6f=6f+6-6f
6=6
Step 3: Subtract 6 from both sides.
6-6=6-6
0=0

All real numbers are solutions.