How long does it take to double a $1,000 investment that pays 6.5% annual interest, compounded monthly?

Which equation can you use to solve this problem?

2p=p(1+0.065/12)^12t
2=(1+0.065/12)^12t
Solve for t
T= [log(2)/ log(1+0.065/12)] /12
T= 10.7 years or if you want to round it would be 11

10.7 years or 11 years

You can use the compound interest formula: A=P(1+interest)^n

A=the new capital
P=the capital invested
n= the #of monthly

Hope this helps (:

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3

Well what if i told you it wouldn’t matter, because in the future the pony dies, depending on what choice you make