A class if 340 students went on a field trip. They took 8 vehicles, some cars and some busses. Find the number of cars and the number of busses they took if each car holds 5 students and each bus holds 55 students.

Step-by-step explanation:

4 buses and 3 cars

Explanation:

Ahh, these questions remind me of my 8th grade days, man I used to die on these questions huehue

Anyways, so let's get to it

Basic algebra, the object which is not in a set quantity, which we have to find, is the "some cars" and the "some buses"

So let the number of cars be x

Let the number of buses be y

So, since there are 7 vehicles,

x

+

y

=

7

Makes sense right

Now, it says that every car can carry 5 students, and every bus can carry 45 students, so in another way, we could represent this by saying

5 x Number of Cars + 45 x Number of buses

thus,

5x + 45y

And since 195 students went on the field trip, this means that

5x +45y = 195

So now we have two equations,

x + y = 7

5x + 45y = 195

We can solve this with substitution

x + y = 7

x = 7 - y

Thus, x = 7-y

Put this in this

5(7-y) + 45y = 195

35 - 5y + 45y = 195

35 +40y = 195

40y = 195 - 35

40y = 160

y = 160/40

y= 4

Thus, the number of buses, y, is 4

Now since there are 7 vehicles, and 4 are buses, then the other 3 are cars

You can double check this

Hope this helped :D