What are the x-intercepts of the graph of the function f(x) = x2 + 4x – 12? (–6, 0), (2,0) (–2, –16), (0, –12) (–6, 0), (–2, –16), (2, 0) (0, –12), (–6, 0), (2, 0)

Use " ^ " to denote exponentiation:     f(x) = x^2 + 4x – 12.to find the x-intercepts, or the roots, or the zeros, set this quadratic = to 0 and solve for x: x^2 + 4x – 12 = 0completing the square,  x^2 + 4x + 4 - 4 – 12 = 0                                          (x+2)^2 = 16x+2 = plus or minus sqrt(16) = plus or minus 4.then the roots are -2+4 and -2 - 4, or 2 and -6.the x-intercepts are (2,0) and (-6,0).

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