Suppose that a machine with a 5-stage pipeline uses branch prediction. 15% of the instructions for a given test program are branches, of which 84% are correctly predicted. The other 16% of the branches su er a 4-cycle mis-prediction penalty. (In other words, when the branch predictor predicts incorrectly, there are four instructions in the pipeline that must be discarded.) Assuming there are no other stalls, develop a formula for the number of cycles it will take to complete n lines of this program

How is the number 110 written when expanded out to place values in the base 2 (binary) number system? options: 2 x 4 + 3 x 2 + 4 x 1 1 x 2 + 1 x 2 + 0 x 2 1 x 100 + 1 x 10 + 0 x 1 1 x 4 + 1 x 2 + 0 x 1

Solve the following javafx application: write a javafx application that analyzes a word. the user would type the word in a text field, and the application provides three buttons for the following: - one button, when clicked, displays the length of the word.- another button, when clicked, displays the number of vowels in the word.- another button, when clicked, displays the number of uppercase letters in the word(use the gridpane or hbox and vbox to organize the gui controls).

This question involves a class named textfile that represents a text file. public class textfile { private string filename; private string filename; private arraylist words; // constructors not shown // postcondition: returns the number of bytes in this file public int filesize() { } // precondition: 0 < = index < words.size() // postcondition: removes numwords words from the words arraylist beginning at // index. public void deletewords(int index, int numwords) { } // precondition: 0 < = index < = words.size() // postcondition: adds elements from newwords array to words arraylist beginning // at index. pub lic voidaddwords(int index, string[] newwords) { } // other methods not shown } complete the filesize() method. the filesize() is computed in bytes. in a text file, each character in each word counts as one byte. in addition, there is a space in between each word in the words arraylist, and each of those spaces also counts as one byte. for example, suppose the words arraylist stores the following words: { mary had a little lamb; its fleece was white as snow. } the filesize() method would compute 4 + 3 + 1 + 6 + 5 + 4 + 6 + 3 + 5 + 2 + 5 as the sum of the lengths of each string in the arraylist. the value returned would be this sum plus 10, because there would also be 10 spaces in between the 11 words. complete the filesize() method below: // postcondition: returns the number of bytes in this file public int filesize() { }