The projected number of people aged 65 and over in the U. S. population with Alzheimer's disease (in millions) is given byP(t) = −0.0002083t 3 + 0.0157t 2 – 0.093t + 5.2 (4 ≤ t ≤ 40);Where t is measured in years and t = 4 corresponds to the year 2014. This model does not claim validity for years 2051 and beyond. Nevertheless, the model does suggest that:

The missing part of the question is;

What is the projected number of people aged 65 and over with Alzheimer's disease in 2030 and in 2050

In 2030, P(20) = 7.9536 (in millions)

In 2050, P(40) = 13.2688 (in millions)

Step-by-step explanation:

We are given that;

Number of people aged 65 and over in the U.S. population with Alzheimer's disease (in millions) as;

P(t) = −0.0002083t³ + 0.0157t² – 0.093t + 5.2 (4 ≤ t ≤ 40);

Where t is measured in years and t = 4 corresponds to the year 2014.

Now,

Since t = 4 represents 2014,therefore;

t = 20 would represent population in 2030

Thus in year 2030;

P(20) = −0.0002083(20)³ + 0.0157(20)² – 0.093(20) + 5.2

P(20) = 7.9536 (in millions)

Also, in year 2050, t will correspond to 40 years.

Thus;

P(40) = −0.0002083(40)³ + 0.0157(40)² – 0.093(40) + 5.2

P(40) = 13.2688 (in millions)

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

25.2

step-by-step explanation:

2+4x6-8/10= 25.2