HELP! The piston of an internal combustion engine
compresses 218 mL of gas. The final pressure
is 15 times greater than the initial pressure.
What is the final volume of the gas, assuming
constant temperature?
Answer in units of mL.

14.53

Explanation:

V1= 218ML

V2= ?

P2= 15P1

USING BOYLE'S LAW

P1V1= P2V2

V2= P1V1/P2

V2 = P1(218ML)/15P1 = 14.53ML

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.