Mercury can be obtained by reacting mercury(II) sulfide with calcium oxide. How many grams of Mercury metal are produced when 2.11 g of calcium oxide reacts with excess mercury(II) sulfide? 4HgS+4CaO=4Hf+3CaS+CaSO4

a. 10.1 g

b. 1.80 g

c. 13.4 g

d. 7.56 g

Option D. 7.56 g of Hg.

Explanation:

The balanced equation for the reaction is given below:

4HgS + 4CaO —> 4Hg + 3CaS + CaSO₄

Next, we shall determine the mass of CaO that reacted and the mass of Hg produced from the balanced equation. This is can be obtained as follow:

Molar mass of CaO = 40 + 16

= 56 g/mol

Mass of CaO from the balanced equation = 4 × 56 = 224 g

Molar mass of Hg = 200.59 g/mol

Mass of Hg from the balanced equation = 4 × 200.59 = 802.36 g

SUMMARY

From the balanced equation above,

224 g of CaO reacted to produce 802.36 g of Hg.

Finally, we shall determine the mass of Hg produced by the reaction of 2.11 g of CaO. This can be obtained as follow:

From the balanced equation above,

224 g of CaO reacted to produce 802.36 g of Hg.

Therefore, 2.11 g of CaO will react to produce = (2.11 × 802.36)/224 = 7.56 g of Hg.

Thus, 7.56 g of Hg were obtained from the reaction.

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6

sry but any answer choices