A 63.5 g sample of an unidentified metal absorbs 355 ) of heat when its temperature changes
by 4.56 °C. Calculate the specific heat capacity of the metal.

0.208 is the specific heat capacity of the metal.

Explanation:

Given:

mass (m)  = 63.5 grams 0R 0.0635 kg

Heat absorbed (q) = 355 Joules

Δ T (change in temperature) = 4.56 degrees or 273.15+4.56 = 268.59 K

cp (specific heat capacity) = ?

the formula used for heat absorbed  and to calculate specific heat capacity of a substance will be calculated by using the equation:

q = mc Δ T

c =

c =

 = 0.208 J/gm K

specific heat capacity of 0.208 J/gm K

The specific heat capacity is defined as  the heat required to raise the temperature of a substance which is 1 gram. The temperature is in Kelvin and energy required is in joules.

so what is the problem with your lab report and whats the subject of the lab report? i will you

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.