Aproton and an electron in a hydrogen atom are separated on the average by about 5.3 × 10−11 m. what is the magnitude of the electric field set up by the proton at the location of the electron? the value of the coulomb constant is 8.99 × 109 n · m2/c2. answer in units of n/c

5.10¹¹ N/C

Explanation:

As we have a proton and a neutron, we can consider that they both have the same charge, this is:

e- = e+ = |1,6x10⁻¹⁹ C| , this number is in absolute value

Then, the formula needed to calculate the magnitude of the electric field from a charged particle is:

E= kqQ/r²

Where:

K= Coulomb constant

Q= charge  

r = distance between two charges

Then:  

E= 8.99x10⁹N/C²*(1.6x10⁻¹⁹C)/(5.3x10⁻¹¹m)²

E=5.12x1011 N/C

It is important that this value is a magnitude, it does not have any sign (positive or negative), for the magnetic field

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g