Consider a population of 1099 apple fly maggots. In this population, you observe that the allele frequency of the dominant allele at the ADH locus, where are are two alleles, is 0.554. What is the expected number of heterozygotes if this population is at HWE (please give your answer as an integer)?

543

Explanation:

Given is the frequency of the dominant allele in the population (p)= 0.554

Since the locus has two alleles and the population is in Hardy Weinberg equilibrium, the frequency of the recessive allele (q) of the same locus would be= 1-0.554= 0.446

Frequency of heterozygous genotype in the given population = 2pq= 2 x 0.554 x 0.446= 0.4941

Now, the number of heterozygous genotype in the given population= 0.4941 x 1099= 543.0159 = 543

i can't see the full page, therefore, can't answer it

explanation:

i'm gonna put a couple so you can chose from

explanation:

if you know the fur color of the offspring mice, you can use the ratios to identify the genotypes of the parents.

if either parent mouse passes a dominant allele, the offspring will have black fur.

if the parental mice has two different fur color (i.e white and black) , the color of the offspring's fur would be either black, white, or the combination of both (grey)

hope this : )