Arectangular page is designed to contain 81 square inches of print. the margins at the top and bottom of the page are each 1 inch deep. the margins on each side are 1½ inches wide. what should the dimensions of the page be so that the least amount of paper is used?

x = 11.02 inch by  y = 7.35 inch

Explanation:

Let the width of the print be = x

Then the width of the page is x + (1.5+1.5) = x + 3

Let the height of the print be = y

Then the height of the page is y + (1+1) = y + 2

Given the area of the print is 81 square inches

That means, xy = 81

Therefore, y =

Therefore, the area of the page is

A = (x + 3)(y + 2)

   = (x + 3)( + 2)

Now for least amount of paper to be used,

x = 11.02 inch

Now y =

          =

          = 7.35 inch

Therefore the dimensions of thr page for the least amount of paper is x = 11.02 inch by  y = 7.35 inch

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