A see-saw has a child weighing 80 pounds on the side where the seat was 10 feet away from the fulcrum and there is a child on the opposite side who weighed 100 pounds. What would be the distance of the 2nd child away from the fulcrum in order for the see-saw to be in static equilibrium

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

this is poiselle's equation from fluid mechanic in physics. mech eng

use photo math tells u all the answers thats what i use