An aluminum sphere is 8.20 cm in diameter. What will be its % change in volume if it is heated from 30∘C to 150 ∘C ?

Change in volume / volume = 3 K change in temperature

K = 24E-6 / deg C     coefficient of linear expansion

R = 4.1 cm

dR / R = 24E-6 * 120 dec C = 2.88E-3

V = 4/3 pi R^3

dV = 4 pi R^2 dR

dV / V = 3 dR / R = 2.88E-3 * 3 = 8.6E-3 = .86%

newton's first law of motion

that would be because of both gravity and friction. so     c