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Physics, 24.06.2021 20:00 kbenitez90

A force parallel to the xx-axis acts on a particle moving along the xx-axis. This force is associated with potential energy U(x)U(x) given by U(x)=αx4U(x)=αx4 , where ααalpha = 0.770 J/m4J/m4 . Part A What is the direction of the force when the particle is at x = -0.800 mm?

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