A 8.25-N force is applied to a 2.50 kg object to accelerate it rightwards. The object encounters 2.19 N of friction. Determine the acceleration of the object. (Neglect air
resistance.)

Explanation:

Use F - f = ma since we are on a flat surface. We are given the applied Force as 8.25, the frictional force as 2.19, and a mass of 2.50. Filling in:

8.25 - 2.19 = 2.50a. Doing the subtraction on the left gives us:

6.06 = 2.50a and we divide to 3 sig figs to get

a = 2.42 m/s/s

the area between the graph and the t axis

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