How far will a brick starting from rest fall freely in 3 seconds

When object falls freely we can say

its initial speed will be ZERO

and its acceleration due to gravity must be

a = g = 9.8 m/s^2a=g=9.8m/s2

Now we need to find the distance of free fall in 3 s of time

So here we will use kinematics

y = v* t + \frac{1}{2} at^2y=v∗t+21at2

now we will plug in all values in it

y = 0 + \frac{1}{2}* 9.8 * 3^2y=0+21∗9.8∗32

y = 44.1 my=44.1m

So it will fall by total distance of 44.1 m

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form