A 1.00 liter flask initially contained 0.24 mol NO2 at 700 K which decomposed according to the following equation. When equilibrium was achieved, 0.14 mol NO was present. Calculate Kc. 2NO2(g) ↔ 2NO(g) + O2(g)

Explanation:

Hello,

In this case, for the given reaction, the equilibrium expression is:

That in terms of the reaction extent is written as (initial concentration of NO2 is 0.24 M for 0.24 mol in 1.00 L):

Moreover, since at the equilibrium 0.14 moles of NO are present (a 0.14-M concentration), we can compute the reaction extent as shown below:

In such a way, knowing , we compute Kc as shown below:

Regards.