If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°c, what will be the volume at 50°c?
a. 0.002021624 m3
b. 0.002010812 m3
c. 0.10812 m3
d. 0.004021624 m3

From tables, the density of mercury is
13545 kg/m^3 at 20°C,
13472 kg/m^3 at 50°C.

Because mass = density * volume, the mass of mercury at 20°C is
m = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg

Let V  = volume of mercury at 50°C.
Because the mass of mercury does not change, therefore at 50°C,
(13472 kg/m^3)*(V m^3) = 27.09
V = 27.09/13472 = 0.0020108 m^3

 B. 0.002010812 m³