When is the magnitude of the acceleration of a mass on a spring at its maximum value?
when the mass has a speed of zero
when the mass is moving upward
when the mass has no displacement
when the mass is 1/2x

when the mass has no displacement

Explanation:

The kinetic energy of the mass reaches its maximum value and therefore its acceleration is maximum, in its equilibrium position, that is, when the spring is not compressed or elongated. Thus, when the mass has no displacement, all the energy of the system is in the form of the kinetic energy of the mass.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

the rearrangement of particles in a physical change. hope this