During a golf game, the ball is hit forward with 500 n of force using a golf club. according to newton's third law of motion, what is the force of the golf ball on the club?

a.
the golf club exerted a forward force of 500 n on the golf ball. this activated a 500 n force of inertia from the golf ball to the golf club.

b.
the golf club exerted a forward force of 500 n on the golf ball, so the golf ball exerted a backward force of 500 n on the golf club.

c.
the golf club exerted an attractive force of 500 n on the golf ball, so the golf ball exerted a repulsive force of 500 n on the golf club.

d.
to determine the force on the golf ball, the force of 500 n by the golf club must be multiplied by gravity to get 4900 n.

Astudent throws a water balloon with speed v0 from a height h = 1.76 m at an angle θ = 21° above the horizontal toward a target on the ground. the target is located a horizontal distance d = 9.5 m from the student’s feet. assume that the balloon moves without air resistance. use a cartesian coordinate system with the origin at the balloon's initial position. (a) what is the position vector, rtarge t, that originates from the balloon's original position and terminates at the target? put this in terms of h and d, and represent it as a vector using i and j. (b) in terms of the variables in the problem, determine the time, t, after the launch it takes the balloon to reach the target. your answer should not include h. (c) create an expression for the balloon's vertical position as a function of time, y(t), in terms of t, vo, g, and θ. (d) determine the magnitude of the balloon's initial velocity, v0, in meters per second, by eliminating t from the previous two expressions.