Two roots of a 3-degree polynomial equation are 5 and -5. Which of the following cannot be the third root of the equation?

Select all that apply.

5

5i

0

-5

-5i

5i and -5i

Step-by-step explanation:

Imaginary roots come in pairs, so the third root must be a real number.  Therefore, neither 5i nor -5i can be the third root.

5i and -5i

Step-by-step explanation:

Both of these would have to be in the equation for either of them to work, and as the problem already told us that there is only a 3rd root, neither will be our answer.

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50- 250 is correct i did that one too

step-by-step explanation:

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1