I need help again NO LINK PLEASE

The Acceleration of the object = 6.4 m/s²

Explanation:

Mass of block (m) = 5 kg

Action force on block, (F₁) = 40 N

To Find:

Acceleration of the object (a) = ?

Required solution:

Frictional force opposing the motion (F₂) = 8 N

Here in this question we have to find Acceleration of the object. So, firstly we have to find Net force of block after that we will find Acceleration of the object on the basis of conditions given above

⇒ Net force = Action force on block - Opposing friction force

⇒ F = F₁ - F₂

⇒ F = 40 - 8

⇒ F = 32 N

Now, we have to two elements that used in formula, Net force and Mass of block.

Net force of the block (F) = 32 N

Mass of block (m) = 5 kg

And we have to find Acceleration of the object.

We can find Acceleration of the object by using the Second law of Newton which says F = ma

Here,

F is the Force in N.

m is the Mass in kg.

a is the Acceleration in m/s².

So let's find Acceleration (a) !

† From second law of Newton

⇛ F = ma

⇛ a = F/m

⇛ a = 32/5

⇛ a = 6.4 m/s²

a. spokes of a wheel.

as indicated in the question radial contains rad, also found in radius, so the fracture's would span the radius.