Physics, 08.10.2019 13:50 gianni0

At exactly 12: 00 noon, how many oscillations will the pendulum have completed?

Answers: 3

Show answers

Answers

Answer from: Ziham

Below is the complete question and

In a science museum, a 110 kg brass pendulum bob swings at the end of a 15.0-m-long wire. The pendulum is started at exactly 8:00 a.m. every morning by pulling it 1.5 m to the side and releasing it. Because of its compact shape and smooth surface, the pendulum's damping constant is only 0.010 kg/s.

At exactly 12:00 noon, how many oscillations will the pendulum have completed?

ANSWER:

The damping time constant is

m/b=11000s.n t2 4 x 3600 $\sqrt{9.8/ 15 - 0.01 x^{2}/ 4 x 110 x^{2} /2 \pi$ = 1852.5

Answer from: caelilou

The pendulum will complete $\boxed{1872}$ oscillations between $8:00\,{\text{am}}$ to $12:00\,{\text{pm}}$ .

Further Explanation:

Given:

The length of the simple pendulum is $15\,{\text{m}}$ .

The pendulum is started at $8:00\,{\text{am}}$ .

The pendulum is stopped at $12:00\,{\text{pm}}$ .

Concept:

The frequency of oscillation of the simple pendulum is given by:

$f=\frac{1}{{2\pi}}\sqrt{\frac{g}{l}}$

(1)

Here, is the frequency of oscillation of pendulum, is the acceleration due to gravity and is the length of the pendulum.

The value of acceleration due to gravity on the surface of Earth is $9.8\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}$

Substitute the values in equation (1).

$\begin{aligned}f&=\frac{1}{{2\pi}}\sqrt{\frac{{9.8}}{{15}}}\\&=\frac{1}{{2\pi}}\left({0.808}\right)\\&\approx0.13\,{\text{Hz}}\\\end{aligned}$

It means that pendulum makes 0.13 oscillation in $1\,\sec$ .

The number of seconds from $8:00\,{\text{am}}$ to $12:00\,{\text{pm}}$ is:

$\begin{aligned}t&=\left({12 - 8}\right)\left({3600\,}\right)\,{\text{s}}\\&=4\times3600\,{\text{s}}\\&=14400\,{\text{s}}\\\end{aligned}$

So number of oscillations completed by the pendulum is:

$\begin{aligned}n7&=f\times t\\&=0.13\times14400\\&=1872\,{\text{oscillations}}\\\end{aligned}$

Thus, the pendulum will complete $\boxed{1872}$ oscillations from $8:00\,{\text{am}}$ to $12:00\,{\text{pm}}$ .

Learn More:

1. Which of the following are units for expressing rotational velocity, commonly denoted by omega?

2. A remote-controlled car is moving in a vacant parking lot. the velocity of the car as a function of time

3. How far must you compress a spring with twice the spring constant to store the same amount of energy?

Answer details:

Grade: High School

Subject: Physics

Chapter: Simple Pendulum

Keywords:

Pendulum, oscillations, 8:00 am, 12:00 pm, length of pendulum 15m, 110kg, brass pendulum, bob swings, frequency of pendulum, number of oscillations.

Answer from: Quest

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

Answer from: Quest

British cologoinst admisitrion

Another question on Physics

Physics, 22.06.2019 08:00

If a substance is in the gas phase, which of qualities of the gas will stay constant? a: volume b: mass c: shape d: position of particles

Answers: 2

Answer

Physics, 22.06.2019 18:30

Both speed and velocity measure how fast something is moving. however, since speed is not a it does not require a(n question 6 options: a) quantity , unit b) magnitude, unit c) scalar, direction d) vector, direction

Answers: 2

Answer

Physics, 22.06.2019 19:50

An air-filled capacitor is formed from two long conducting cylindrical shells that are coaxial and have radii of 26 mm and 103 mm. the electric potential of the inner conductor with respect to the outer conductor is - 700 v (k = 1/4πε 0 = 8.99 × 109 n · m2/c2) the energy stored in a 1.0-m length of this capacitor is closest to

Answers: 1

Answer

Physics, 22.06.2019 21:10