A pebble is thrown into the air with a velocity of 19/m at an angle of 36 with respect to the horizontal. if air resistance is negligible, what is the maximum height the pebble reaches?
A. 6.4 m
B. 8.0 m
C. 11 m
D. 19 m

The maximum height the pebble reaches is approximately;

A. 6.4 m

Explanation:

The question is with regards to projectile motion of an object

The given parameters are;

The initial velocity of the pebble, u = 19 m/s

The angle the projectile path of the pebble makes with the horizontal, θ = 36°

The maximum height of a projectile, , is given by the following equation;

Therefore, substituting the known values for the pebble, we have;

Therefore, the maximum height of the pebble projectile, ≈ 6.4 m.

newton's first law of motion