the displacement time graph for a body is given below. State whether the velocity and acceleration of body in region BC, CD, DE and EF are positive, negative or zero

be subject to a force andchange its motion

the ima (higher than 1m) will be greater than the ima with the height of 1m.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j