Un cuerpo se lanza hacia arriba con 50 m/s . ¿A qué altura se encuentra cuando su rapidez es 20 m/s por segunda vez? (g = 10 m/s ^ 2) .

105 m

Explanation:

Given that the initial velocity of the body, u= 50 m/s in upward direction.

Acceleration due to gravity, g= 10 m / in the downward direction.

Let h be the height of the body when the velocity of the body is 20 m/s.

As the gravitational force acting in the downward direction, so taking it negative as

a= - 10 m/  in the upward direction.

By using the equation of motion ...(i)

Here, u= 50 m/s

v= 20 m/s

s=h

Putting all the values in the equation (i), we have

Hence, the height of the body is 105 m.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

true tan speed = ang vel x radius