A series RLC circuit has resistance R = Ω, inductive reactance XL = Ω, and capacitive reactance XC = Ω. If the maximum voltage across the resistor is ΔVR = V, find the maximum voltage across the inductor and the capacitor.

Explanation:

The question is incomplete. Here is the complete question.

A series RLC circuit has resistance R = 12Ω, inductive reactance XL = 30Ω, and capacitive reactance XC = 20Ω. If the maximum voltage across the resistor is ΔVR = 145V, find the maximum voltage across the inductor and the capacitor.

a) Voltage across the inductor is expressed as

VL = IXL

I is the current flowing in the inductor

XL is the inductive reactance

First we need to get I

According to ohms law, VR = IR

I = VR/R

I = 145/12

I = 12.08A

Since all the elements are in series, then the same current will flow in them.

Given XL = 30Ω

VL = 12.08(30)

VL = 362.5V

Hence the maximum voltage across the inductor is 362.5V

b) Voltage across the capacitor VC = IXC

Given

I = 12.08A

XC = 20Ω

VC = 12.08*20

VC = 241.67V

Hence the maximum voltage across the capacitor is 241.67V

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .

we need answer choices