During a firework display, a shell is shot through the air with an initiak speed of 70 m/s at an angle of 75° above the horizontal. The fuse is timed to ignite the shell just as it reaches its highest point above the ground. Calculate the height at which the shell explodes

241.24m

Explanation:

The height at which the shell explodes will be at the maximum height. In projectile motion, maximum height formula is expressed as:

H = u²sin²θ/2g

u is the initial speed = 70m/s

θ the angle of launch = 75°

g is the acceleration due to gravity = 9.81m/s²

Substitute the values into the formula and get H

H = 70²(sin75°)/2(9.81)

H = 4900sin75°/19.62

H = 4900*0.9659/19.62

H = 4733.037/19.62

H = 241.24m

Hence the height at which the shell explodes is 241.24m