B) A car runs at a constant speed of 15 m/s for 300 s and then accelerates uniformly
to a speed of 25 m/s over a period 20 s.
This speed is maintained for 300 s before
the car is brought to rest with uniform
deceleration in 30 s.
1) Sketch the velocity-time graph to
represent the journey described
above.

Letter a, because when there are unlike charges they will always attract to each other.

Answermake them get very hot and over time wear them out;

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.