Consider a car with a mass of 1250 kg moving at a constant speed of (22.0 A) m/s in a circular off ramp with a radius of (65.0 +B) m. What does the coefficient of static friction have to be for the car to just maintain its motion of ramp? Give your answer to 3 significant figures. A=7
B=2

Explanation:

weight of the car mg = m g

frictional force acting on the car = μ mg where μ is coefficient of friction

= m μ g

This force provides centripetal force , hence

m μ g  = m v² / R

μ = v² / rg

= 22 x 22 / 65 x 9.8

= .759  

i feel your pain too because i cant find my dad and hes been missing for 17 years of my life

explanation:

he went to the supermarket with your dad

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5