Traveling at an initial speed of 1.5 x 106 m/s, a proton enters a region of constant magnetic field of magnitude 1.5 t. if the proton's initial velocity vector makes an angle of 30 with the magnetic field, compute the proton's speed 4 s after entering the magnetic field. 0 a. 5.0 x 105 m/s o b. 7.5 x 105 m/s ° c. 1.5 x 106 m/s 0 d. 3.0 x 106 m/s

C)

Explanation:

As we know that force on a moving charge due to magnetic field is given by

so from above formula we can see that

force on moving charge is always perpendicular to the velocity on charge moving in constant magnetic field

So the work done by this force on moving charge is always zero

so this force can change the direction of velocity of charge but it can not change the magnitude of speed of the charge

so at all instants of time the speed will remain the same

so after t = 4 s the speed of the charge is given as

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

answer; equivalent to a one(1) horsepower motor;