The magnetic field at the center of a 0.60-cm-diameter loop is 2.7 mT . What is the current in the loop

12.898A

Explanation:

The formula for calculating the magnetic field in the loop bus expressed as;

B = Iμ0/2r

Given

Diameter d = 0.60cm

Radius r = d/2 = 0.30cm

r = 0.0030m

Permittivity of free space μ0 = 4π×10^-7

Magnetic field strength B = 2.7×10^-3T

Substitute into the formula and get I

2.7×10^-3 = 4π×10^-7I/2(0.0030)

2.7×10^-3 = 4π×10^-7I/0.0060

Cross multiply

2.7×10^-3 × 6.0×10^-3 = 4π×10^-7I

16.2×10^-6 = 4π×10^-7I

I = 16.2×10^-6/4π×10^-7

I = 16.2×10^-6/4(3.14)×10^-7

I = 16.2×10^-6/12.56×10^-7

I = 1.2898×10^{-6+7}

I = 1.2898×10

I = 12.898A

Hence the current in the loop is 12.898A

no. dot product   =0 when vecs at right angles

answer: the metamorphic rocks are formed when they are exposed to high pressure and high temperatures. this happens when one of the earth's plates comes in contact with the other plate by traveling in opposite directions, straight into each other or slipping under one another. the friction that is caused by this activity results in   melting of rocks and when it cools they are known as metamorphic rocks. this process needs a controlled amount of pressure and temperature otherwise it may turn into magma.