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Physics, 19.10.2020 14:01 alexianunez15

A stone is projected vertically upward with a velocity of 20 metre per second. 2 seconds later a second stone to is similarly projected with the same velocity when the two stones meet the second one is rising at a velocity of 10 metre per second neglecting air resistance calculate the length of time the second stone is in motion before they meet to velocity of the first Stone when they meet take g equals to 10 metre per second

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