A force applied to a 0.25 Kg hockey puck gives the puck an acceleration of 16 m/s2. What acceleration would the same force give to a 0.50 Kg baseball?

8 m/s².

Explanation:

We'll begin by calculating the force applied to 0.25 Kg hockey puck. This is illustrated below:

Mass (m) = 0.25 Kg

Acceleration (a) = 16 m/s²

Force (F) =.?

Force (F) = mass (m) × acceleration (a)

F = ma

F = 0.25 × 16

F = 4 N

Therefore, a force of4 N was applied to the 0.25 Kg hockey puck.

Finally, we shall determine the acceleration in which the 4 N force will give to the 0.50 Kg baseball. This can be obtained as follow:

Mass (m) = 0.50 Kg

Force (F) = 4 N

Acceleration (a) =?

F = ma

4 = 0.5 × a

Divide both side by 0.5

a = 4 / 0.5

a = 8 m/s²

Therefore, the same force (i.e 4 N) applied to the hockey puck will give the 0.5 kg baseball an acceleration of 8 m/s².

f=ma newton

f=100x2.5=250n