A car weighs 2,000 kg. It moves along a road by applying a force on the road with a parallel component of 560 N. There are two passengers in the car, each weighing 55 kg. If the magnitude of the force of friction experienced by the car is 45 N, what is the acceleration of the car?

The acceleration of the car is 4.10 m/s².

Explanation:

The acceleration of the car can be found using the following equation:

   (1)

Where:

F is the force

m is the mass

a is the acceleration

The force is:

  (2)

Where:

F(p) is the parallel force = 560 N

F(f) is the force of friction = 45 N

By entering equation (2) into (1) we have:

Therefore, the acceleration of the car is 4.10 m/s².

I hope it helps you!

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

it was given as a lesson and guide for prayer.