A cyclist exerts a constant driving force of magnitude FN while moving up 36 a straight hill inclined at an angle a to the horizontal, where sin a = 325 constant resistance to motion of 32 N acts on the cyclist. The total weight of the cyclist and his bicycle is 780 N.
The cyclist's acceleration is -0.2 ms.

(i) Find the value of F. The cyclist's speed is 7 ms at the bottom of the hill.

(ii) Find how far up the hill the cyclist travels before coming to rest.

cant without the picture! ?

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.