Coherent light with wavelength 460 nm falls on a pair of slits. On a screen 1.86 m away, the distance between dark fringes is 3.90 mm. What is the slit separation?

The slit separation of the given experiment will be m or 0.21938 mm.

Given information:

The wavelength of the coherent light which falls on a pair of slits is nm.

The distance between slits and screen is m.

The fringe width is given as mm.

For a double-slit experiment, the slit separation, d, can be calculated as,

Therefore, the slit separation of the given experiment will be m or 0.21938 mm.

For more details, refer to the link:

link

The split separation d = 2.12 * 10^-4 m

Explanation:

Mathematically, for a double split interference, the relation between separation of slit and fringe width is given by the formula;

d = Rλ/Δy

Where R represents the distance of screen from the slit given as 1.86m , λ is the wavelength of incident light given as 460 nm ,

Δy is the fringe width given as 3.90 nm

plugging these values into the equation, we have;

d = (1.86)(460 * 10^-9)/(3.9 * 10^-3)

d = 2.12 * 10^-4 m

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.