Two projectiles are thrown from the same point with the velocity of49ms-1. First is projected making an angle with the horizontal and the second at an angle of (90- ). The

second is found to rise 22.5m higher than the first. Find the heights to which each will rise?

Height of the first projectile = 49.98 m

Height of the second projectile = 72.52 m

Explanation:

From the given information;

Two projectiles are thrown from the same point with the velocity of49m/s

First is  projected making an angle  θ with the horizontal

and the second at an angle of 90 - θ.

Thus; for the first height to the horizontal; we have;

 ----- (1)

the second height in the vertical direction is :

   -----(2)

However; the second is found to rise 22.5 m higher than the first; so , we have :

Let's recall that :

Cos²θ = 1 - Sin²θ

Replacing it into above equation; we have:

From (1);

Height of the first projectile = 49.98 m

Similarly;

From(2)

Height of the second projectile = 72.52 m

massxgravity x heght=weightxheight= pe

4900=490xh

h=10

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.