An object of mass 50 g and density 5 g/cm3 is carefully lowered into a measuring cylinder containing 50 cm3 of water. What will the final volume reading be?

60cm^3

Explanation:

Here we can use the relationship:

Density = mass/volume.

We know that density = 5g/cm^3 and mass = 50g, then we have:

5g/cm^3 = 50g/V

V = 50g/5g/cm^3 = 10cm^3

Then, when we introduce it in a cylinder with 50cm^3 of water, this is heavier than water (the density of the water is 1g/cm^3) it will sink, and the complete volume will be equal to the volume of the water plus the volume of the object:

Total Volume = 50cm^3 + 10cm^3 = 60cm^3

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f=ma newton

f=100x2.5=250n