An AC source with an output rms voltage of 27.0 V at a frequency of 60.0 Hz is connected across a 12.2-µF capacitor. (a) Find the capacitive reactance. Ω (b) Find the rms current. A (c) Find the maximum current in the circuit. A (d) Does the capacitor have its maximum charge when the current has its maximum value? Yes No Explain. This answer has not been graded yet.

Explanation:

a) capacitive reactance Xc = 1/2πfC

f is the frequency of the AC source

C is the capacitance of thw capacitor

Given f = 60.0Hz

C = 12.2-µF

C = 12.2 × 10^-6Farads

Xc = 1/2π×60×12.2×10^-6

Xc = 1/0.004599

Xc = 217.44ohms

b) Using the formula Vrms = IrmsXc Vrms

Irms = Vrms/Xc

Irms = 27.0/217.44

Irms = 0.124Amperes

c) Since Irms = Im/√2

Where Im is the maximum current

Im = Irms×√2

Im = 0.124× √2

Im = 0.088A

d) No, the capacitor has no charge when the current is at maximum.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.