Abox has a momentum of 1.30 kg*m/s to the right. a 12.8 n force pushes it to the right for 0.218 s. what is the final momentum of the box.

4.09 kgm/s

Explanation:

Concept tested: Second Newton's law of motion

So what does the second Newton's law of motion state?

In this case;

Therefore; replacing the values of the variables in the formula;

we get;

Solving for final momentum;

      = 4.09 kgm/s

Therefore, the final momentum of the box is 4.09 kgm/s

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂