A force of 880 newtons stretches a spring 4 meters. A mass of 55 kilograms is attached to the end of the spring and is initially released from the equilibrium position with an upward velocity of 12 m/s. Find the equation of motion. x(t)

Explanation:

This problem describes a system experimenting a simple harmonic motion. The spring constant is determined by the Hooke's Law:

The angular frequency is:

The position and velocity functions for the motion of the mass-spring system is:

The initial condition for the system are:

,

Equation at initial time are:

By dividing the first equation by the second one:

Which corresponds to

The amplitude is:

The equation of motion is:

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answer: i'm not sure which is which for i get confused on it all the time but i can tell you that the answer lies with the convex and concave devices. i hope this you. have a good day and best of luck to you!

explanation: