The 1 kg box is sliding along a frictionless surface. it collides with and sticks to the 2 kg box. afterward, the speed of the two boxes is

The speed of the boxes are 1 m/s.

Explanation:

Given that,

Mass of box = 1 kg

Mass of another box = 2 kg

Suppose 1 kg box moves with 3 m/s speed.

We need to calculate the speed of the boxes

Using formula of conservation of momentum

Where, u = initial velocity

v = final velocity

Put the value into the formula

Hence, The speed of the boxes are 1 m/s.

two charges are fixed in place on the x-axis as shown. the charge at x = 0 is negative and has magnitude q = 2 μcoulombs (1 μcoulomb = 10-6 coulombs). the charge at x = d, (d = +12 cm), is positive and has magnitude q = 4 μcoulombs. find a point x = xo along the x-axis at which the electric field is zero.

the area between the graph and the t axis