A planet orbits a star in an elliptical orbit. At a particular instant the momentum of the planet is <-3.9 x 10^29, -1.6 x 10^29, 0> kg*m/s, and the force on the planet by the star is <-3.3 x 10^22, -1.9 x 10^23, 0> N. Find FlI and FI_ (Express your answers in vector form.)

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

we need to know the time interval during which the force acts. impulse of force = momentum change